LeetCode contest 187 1437. 是否所有 1 都至少相隔 k 个元素 Check If All 1's Are at Least Length K Places Away
LeetCode contest 187 1437. 是否所有 1 都至少相隔 k 个元素 Check If All 1's Are at Least Length K Places AwayTable of Contents一、中文版二、英文版三、My answer四、解题报告一、中文版给你一个由...
LeetCode All in One 题目讲解汇总(持续更新中...)
终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 如果各位看官们,大神们发现了任何错误,或是代码无法通过OJ,或是有更好的解法,或是有任何疑问,意见和建议的话,请一定要在对应的帖子下面评论区留言告知博主...
[LeetCode] Shortest Distance from All Buildings 建筑物的最短距离
You want to build a house on an empty land which reaches all buildings in the shortest amount of distance. You can only move up, down, left ...
[LeetCode] All O`one Data Structure 全O(1)的数据结构
Implement a data structure supporting the following operations: Inc(Key) - Inserts a new key with value 1. Or increments an existing key b...
[LeetCode] Substring with Concatenation of All Words 串联所有单词的子串
You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s&...
LeetCode:Substring with Concatenation of All Words (summarize)
You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that is a...
LeetCode - 30. Substring with Concatenation of All Words
30. Substring with Concatenation of All Words Problem's Link ---------------------------------------------------------------------------- ...
LeetCode 30 Substring with Concatenation of All Words(与所有文字串联子串)(*)
翻译 给定一个字符串S,一个单词的列表words,全是相同的长度。 找到的子串(多个)以s即每个词的字串联恰好一次并没有任何插入的字符所有的起始索引。 原文 You are given a string, s, and a list of words, words, that are all of ...
[LeetCode] Substring with Concatenation of All Words
I think the following code is self-explanatory enough. We use an unordered_map<string, int> counts to record the expected times of eac...
[LeetCode]30.Substring with Concatenation of All Words
【题目】 You are given a string, S, and a list of words, L, that are all of the same length. Find all starting indices of substring(s) in S that...
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