算法Java rust 的相关内容

【算法】5859. 差的绝对值为 K 的数对数目（java / c / c++ / python / go / rust）

5859. 差的绝对值为 K 的数对数目：给你一个整数数组 nums 和一个整数 k ，请你返回数对 (i, j) 的数目，满足 i < j 且 |nums[i] - nums[j]| == k 。|x| 的值定义为：如果 x >= 0 ，那么值为 x 。如果 x < 0 ，那么值...

【算法】1720. 解码异或后的数组（java / c / c++ / python / go / rust）

1720. 解码异或后的数组：未知整数数组 arr 由 n 个非负整数组成。经编码后变为长度为 n - 1 的另一个整数数组 encoded ，其中 encoded[i] = arr[i] XOR arr[i + 1] 。例如，arr = [1,0,2,1] 经编码后得到 encoded = [1...

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【算法】1480. 一维数组的动态和（java / c / c++ / python / go / rust）

1480. 一维数组的动态和：给你一个数组 nums 。数组「动态和」的计算公式为：runningSum[i] = sum(nums[0]…nums[i]) 。请返回 nums 的动态和。样例 1输入： nums = [1,2,3,4] 输出： [1,3,6,10] 解释：动态和计算过程为 [1,...

【算法】1863. 找出所有子集的异或总和再求和（java / c / c++ / python / go / rust）

1863. 找出所有子集的异或总和再求和：一个数组的异或总和定义为数组中所有元素按位 XOR 的结果；如果数组为空，则异或总和为 0 。例如，数组 [2,5,6] 的异或总和为 2 XOR 5 XOR 6 = 1 。给你一个数组 nums ，请你求出 nums 中每个子集的异或总和...

【算法】1929. 数组串联（java / c / c++ / python / go / rust）

1929. 数组串联：给你一个长度为 n 的整数数组 nums 。请你构建一个长度为 2n 的答案数组 ans ，数组下标从 0 开始计数，对于所有 0 <= i < n 的 i ，满足下述所有要求：ans[i] == nums[i]ans[i + n] == nums[i]具体而言...

【算法】1920. 基于排列构建数组（java / c / c++ / python / go / rust）

1920. 基于排列构建数组：给你一个从 0 开始的排列 nums（下标也从 0 开始）。请你构建一个同样长度的数组 ans ，其中，对于每个 i（0 <= i < nums.length），都满足 ans[i] = nums[nums[i]] 。返回构建好的数组 ans 。从 0...

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