LeetCode 331. Verify Preorder Serialization of a T
DescriptionOne way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a...
【LeetCode】Verify Preorder Serialization of a Binary Tree(331)
1. Description One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it...
[LeetCode] Construct Binary Tree from Preorder and Inorder Traversal
链接:https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/description/难度:Medium题目:105. Construct Binary Tree from Pre...
[LeetCode] Verify Preorder Serialization of a Binary Tree 验证二叉树的先序序列化
One way to serialize a binary tree is to use pre-oder traversal. When we encounter a non-null node, we record the node's value. If it is a null node, ...
[LeetCode] Verify Preorder Sequence in Binary Search Tree 验证二叉搜索树的先序序列
Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the seq...
[LeetCode] Binary Tree Preorder Traversal 二叉树的先序遍历
Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return&nbs...
[LeetCode] Construct Binary Tree from Preorder and Inorder Traversal 由先序和中序遍历建立二叉树
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 这道题要求用先序和中序遍...
[LeetCode]Binary Tree Preorder Traversal
题目:给定一颗二叉树,用非递归的前序遍历方法遍历这颗树 算法: 将根节点压入栈中 若栈非空,则运行循环 取出栈顶二叉树节点 訪问节点 压入节点的右孩子 压入节点的左孩子 /** * Definition for binary tree * public class TreeNode { * int ...
LeetCode 144 Binary Tree Preorder Traversal(二叉树的前序遍历)+(二叉树、迭代)
版权声明:转载请联系本人,感谢配合!本站地址:http://blog.csdn.net/nomasp https://blog.csdn.net/NoMasp/article/details/50931535 翻译 给定一个二叉树,返回其前序遍历的节点的值。 例如: 给定二叉树为 {1,#, 2, ...
[LeetCode] Binary Tree Preorder Traversal
This is a fundamental and yet classic problem. I share my three solutions here: Iterative solution using stack --- O(n) time and O(n)&n...
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