[LeetCode] Reverse Linked List II
The basic idea is as follows: Create a new_head that points to head and use it to locate the immediate node before them-th (notice...
[LeetCode] Palindrome Linked List
The idea is not so obvious at first glance. Since you cannot move from a node back to its previous node in a singly linked list, we choose to reverse ...
[LeetCode] Linked List Cycle II
Again, a classic interview question of linked list. Similar to Linked List Cycle, we maintain two pointers fast and slow: fast move two steps at ...
[LeetCode] Linked List Cycle
A classic interview question of linked list. The idea is to maintain two pointers, one move one step at a time and the other move two steps at a time....
[LeetCode] Reverse Linked List II
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, re...
[LeetCode] Reverse Linked List(递归与非递归反转链表)
Reverse a singly linked list. 解题思路 对于非递归实现,思路是依次将从第二个结点到最后一个结点的后继设为头结点,然后将该节点设为头结点(需记住将原头结点的后继设为空)。 对于递归实现,首先反转从第二个结点到最后一个结点的链表,然后再将头结点放到已反转链表的最后,函数返回...
[LeetCode] Linked List Cycle II
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space?...
[LeetCode] Linked List Cycle
Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 解题思路 使用快慢两个指针,如果快的指针赶上了慢的,则说明存在回路。 实现代码...
[LeetCode 第11题] -- Linked List Cycle II
题目链接: Linked List Cycle II 题目意思: 给定一个链表,如果链表有环求出环的起点,否则返回NULL 解题思路: 1. 判断链表是否有环: 两个指针,一个一次走一步,一个一次走两步,如果指针相遇说明有环,否则无环。 ...
[LeetCode 第10题] -- Linked List Cycle
题目链接: linked List Cycle 题目意思: 给定一个链表,判断链表是否有环 代码: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * Lis...
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