面试算法动态规划子序列hard 的相关内容

【面试算法——动态规划 21】不同的子序列（hard）&& 通配符匹配（hard）

115. 不同的子序列给你两个字符串 s 和 t ，统计并返回在 s 的子序列中 t 出现的个数，结果需要对 109 + 7 取模。链接：：https://leetcode.cn/problems/distinct-subsequences/示例 1：输入：s = “rabbbit”, t = ...

【面试算法——动态规划 19】最长回文子序列&& （hard）让字符串成为回文串的最少插入次数

516. 最长回文子序列给你一个字符串 s ，找出其中最长的回文子序列，并返回该序列的长度。子序列定义为：不改变剩余字符顺序的情况下，删除某些字符或者不删除任何字符形成的一个序列。示例 1：输入：s = “bbbab”输出：4解释：一个可能的最长回文子序列为 “bbbb” 。示例 2：输入：s = ...

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更新时间 2023-12-28 14:36:41

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